Sets
a set is a collection of objects, which are called the ‘elements’ of the set
- a ∈ A means that ‘a’ is an element of A (A is the set)
- sets are equal if and only if they have the same elements
- order and repetition don’t matter for sets
- note that a set doesn’t equal its elements, i.e. {a} ≠ a
Cardinality
the cardinality of a set is the number of elements in the set
- cardinality is denoted by |A|
Empty set
- the empty set is denoted by {} or ∅
Universal set
the universal set is the set containing all elements of all sets needed to discuss a topic
- denoted by U
- e.g. U might be ℝ in Calculus, or ℂ in algebra
Basic notation
The following format is used to indicate a set
S = { x ∈ A … }
which is read as “x is an element of A (x ∈ A
) such that (|
) some property is true (…
).
For example, S = { x ∈ ℤ | –2 < x < 5 }
which is equal to { –1, 0, 1, 2, 3, 4 }
.
Venn diagrams
- when solving a problem using Venn diagrams, you must state what each of the subsets means before you draw the diagram
- note that often you can use inclusion-exclusion principle (covered later) rather than Venn Diagrams
Subset
A is a subset of B if and only if every element of A is also an element of B
- A ⊆ B indicates that A is a subset of the set B
- A is the proper subset of B, A ⊂ B, if A ⊆ B but A ≠ B
The following properties are useful:
- if A = B then A ⊆ B and B ⊆ A
- if A ⊂ B then A ⊆ B
- if A ⊆ B and B ⊆ A then A = B (this is used to prove that two sets are equal)
- A is a proper subset of B if it is a subset of B and B has at least one element that is not also in A
The subset relationship only exists between two sets, i.e. for A ⊆ B, A must be a set.
Proving A is a subset of B
- Show that any element of A is also an element of B
- “Let x ∈ LHS” and work to show that x ∈ RHS also.
- “Thus we have shown that any element of the LHS is also an element of the RHS, therefore LHS ⊆ RHS”
Proving A is a proper subset of B
- Prove A ⊆ B as above
- Then find one or more example of an element that is in B but not in A
Proving A = B
- Show A ⊆ B and B ⊆ A, i.e. two iterations of the process above
Power set
The power set of a set is the set of all subsets of the set.
- given a set A, then power set of A is the set of all of the subsets of the set S
- the power set of S is denoted by P(S)
For example,
P({ 0, 1, 2 }) = {
∅,
{ 0 }, { 1 }, { 2 },
{ 0, 1 }, { 1, 2 },
{ 0, 1, 2 },
}
Note: For a set X, X ∈ P(S) and X ⊆ S mean the same thing
Cardinality of a power set
If | A | = n then | P(A) | = 2n
Or, in English, the size of the power set is equal to 2n where n is the number of elements in the set.
Set algebra
Union
The union of the sets A and B is the set that contains the elements that are either in A or in B, or in both.
- denoted by A ∪ B
-
A ∪ B = { x x ∈ A or x ∈ B }
Intersection
the set containing elements that in both A and B
- A ∩ B
Disjoint sets
two sets are disjoint if their intersection is the empty set (i.e. they have no elements in common)
Set difference
The difference of A and B, A – B, is the set containing elements in A but not in B.
- Note that A – B ≠ B – A
- Note that A ∩ Bc = A – B
Complement
The complement of A is Ac. Ac = U – A is the set of elements in U but not in A.
Laws of set algebra
- Commutative laws: A ∪ B = B ∪ A and A ∩ B = B ∩ A
- Associative laws: A ∪ (B ∪ C) = (A ∪ B) ∪ C and A ∩ (B ∩ C) = (A ∩ B) ∩ C
- Distribute laws: A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C) and A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C)
- Idempotent laws: A ∪ A = A and A ∩ A = A
- Double complement laws: (Ac)c = A
- De Morgan’s laws: (A ∪ B)c = Ac ∩ Bc and (A ∩ B )c = Ac ∪ Bc
- Identity laws: A ∪ ∅ = A and A ∩ U = A
- Domination laws: A ∪ U = U and A ∩ ∅ = ∅
- Intersection and union with complement: A ∩ Ac = ∅ and A ∪ Ac = U
- Alternative representation for set difference: A – B = A ∩ Bc
Keep in mind: the property of duality (‘dual’) means that you can swap ∩ and ∪, and swap ∅ and U. This helps you to remember less, which is good.
Generalised union and intersection
See your textbook or course notes for this stuff; it’s hard to write in HTML.
Disjoint
As above,
two sets are disjoint if their intersection is the empty set (i.e. they have no elements in common)
Pairwise disjoint
Sets A1, A2, …, An are pairwise disjoint if and only if Ai ∩ Aj = ∅ whenever i ≠ j
(i.e. any 2 sets have no overlapping elements)
Partition
A set of non-empty sets { A1, A2, …, An } is a partition of a set A if and only if
- A = A1 ∪ A2 ∪ … ∪ An
- A1, A2, …, An are pairwise disjoint
(i.e. all of the sets combine to produce the whole, but none of the sets have the same elements)
Cartesian product
A × B is the cartesian product is the set of all ordered pairs (a, b) where a ∈ A and b ∈ B.
- Note that A2 = A × A
For example,
let A = { 1, 2 }
let B = { 2, 3 }
then
A × B = { (1, 2), (1, 3), (2, 2), (2, 3) }
We can also think of these as xy co-ordinate pairs, and they can be sketched on a number plane as such.
Functions
A function ƒ from a set X to a set Y is a subset of X × Y with the property that for each x ∈ X, there is exactly one ordered pair (x, y) ∈ ƒ.
Takeaways from that definition’s mess:
- a function is a set.
- each x value can only be paired with one y value.
The function
ƒ : X → Y
has X as the domain and Y as the codomain (the codomain is the set containing all of the y values that could occur).
Floor and ceiling
For any x ∈ ℝ,
Floor: the largest integer that is less than or equal to x. Written as ⌊x⌋.
Ceiling: the smallest integer that is greater than or equal to x. Written as ⌈x⌉.
For example, ⌊π⌋ = 3, ⌈π⌉ = 4
Range
The range of a function ƒ : X → Y is the set of all y ∈ Y such that there is an ordered pair (x, y) in ƒ. That is, { y ∈ Y | (x, y) ∈ ƒ for some x ∈ X }
More or less, the set of all the y values that actually occur.
One-to-one
A function ƒ is one-to-one (or injective) if and only if for each y in the codomain there is only one (i.e. one or none at all) ordered pair (x, y) in ƒ.
i.e., ƒ is one-to-one means that if ƒ(x1) = ƒ(x2), then x1 = x2.
- recall from Calculus that increasing functions (ƒ′(x) > 0) are one-to-one and that the horizontal line test can be used
Onto
A function ƒ : X → Y is onto (or surjective) if and only if for every element y ∈ Y there is an element x ∈ X with y = ƒ(x).
i.e., a function is onto if its range equals its codomain.
Bijection
A function is a bijection if it is both one-to-one and onto.
Composition of functions
Let g : X → Y and ƒ : Y → Z. Then the composition of ƒ and g, ƒ ∘ g, is the function from X to Z defined by (ƒ ∘ g)(x) = ƒ(g(x)).
- for proofs involving composition you will possibly need to “take f (or g) of both sides”
Inverse functions
Let ƒ : X → Y. If ƒ is a bijection, then there is a function g : Y → X which, given any y ∈ Y, g(y) is the element x ∈ X such that y = ƒ(x). i.e., g(y) = x and y = ƒ(x)
- g is called the inverse function of ƒ, written as ƒ–1
Composition of a function and its inverse
If ƒ “does something” to a variable, then ƒ-1 “undoes” it.
- ƒ-1 ∘ ƒ is the function i—called the identity function. It does nothing.
Applying a function to many elements
Let ƒ be a function from X to Y. If A ⊆ X, then ƒ(A) = { ƒ(x) x ∈ A} If B ⊆ Y, then ƒ–1(B) = { x ∈ X ƒ(x) ∈ B}, i.e. the set of all x that produce elements of B.
This is kind of hard to understand. Consider an example.
Let ƒ : ℝ → ℝ, ƒ(x) = x2
If A = { x ∈ ℝ 2 < x < 3 } then
ƒ(A) = { ƒ(x) x ∈ A } (Note: ƒ(x) = 2, y = 2)
∴ ƒ(A) = { x2 2 < x < 3}
= { y ∈ ℝ 4 < y < 9 }
And the inverse,
If B = { y ∈ ℝ 1 ≤ y < 16 } then
ƒ–1(B) = { x ∈ X ƒ(x) ∈ B} and so
ƒ–1(B) = { x ∈ ℝ 1 ≤ x2 < 16}
= { x ∈ ℝ –4 < x ≤ –1 } ∪ { x ∈ ℝ 1 ≤ x < 4 }
Sequences and summations
Note: For these sections, I write ∑(a, b) ƒ(x) for a sum from a to b, because writing it out properly is almost impossible. The best approximation is ∑ba, which doesn’t look great.
Sequence
A sequence is a function with domain a subset of ℤ.
- more or less a list
- order and repetition important
- finite sequence is called a string
Basic sums
Memorise these:
∑(j = 0, n) a×rj) = a(rn + 1 – 1) ÷ (r – 1)
∑(j = 1, n) 1 = 1 + 1 + … + 1 [n times] = n
∑(j = 0, n) j = (1/2) × n(n + 1)
∑(j = 1, n) j2 = (1/6) × n × (n + 1) × (2n + 1)
Note: for these last two, j = 0 and j = 1 give the same result.
Also note,
25 × ∑(k = 1, 12) 1 = 25 × 12 not 25 × 1
Addition of sums
Without adding excessive notation, the following are true
∑ (a + b) = ∑ a + ∑ b
∑ (a – b) = ∑ a – ∑ b
Multiplication by a constant
∑ c × ak = c × (∑ ak)
i.e., we can pull out a constant factor
Shifting the index of summation
- too confusing and awkward to write in HTML; see your course notes or textbook
Telescoping sums
- write out sums in full so that you can identify which of the terms cancel and then you can easily add the rest
- i.e. manually expand then see what you can get rid of
- watch out for negatives
- try to make the expression being summed the same in the two sequences
∏ means product